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Mathematics 7 Online
OpenStudy (anonymous):

FFactorize and explain the solution 25 + 12xy - 4xy^2 - 12xy

OpenStudy (saifoo.khan):

\[25-4 x y^2 \]

OpenStudy (chaise):

Can be re-written as: \[-4xy^2 +12xy-12xy+25\] Firstly your middle terms cancel off. You are left with: \[-4xy^2+25\] I don't think this can be'factorised' anymore.

OpenStudy (anonymous):

how u got the ans.

OpenStudy (chaise):

Well, simply when you have +12xy and -12xy they cancel each other out to give zero

OpenStudy (chaise):

Seeing as though it's jut zero it's disregarded in the equation.

OpenStudy (anonymous):

(5 + 2x - 3y)(5 - 2x + 3y) is given in my book

OpenStudy (chaise):

Your question does not match your answer - either in your book, or you have transferred the question onto OpenStudy incorrect. \[25 + 12xy - 4xy^2 - 12xy \neq (5+2x-3y)(5-2x+3y)\]

OpenStudy (anonymous):

|dw:1315566872950:dw|u have 2 factorize dude using the methon of

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