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Please help 2x^-8 is this correct??? 1/2x^8
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definitely...
Thanks :)
depends. If you mean \[2x^{-8}\] then that is equal to \[\frac{2}{x^8}\] If you mean \[(2x)^{-8}\] then that is equal to \[\frac{1}{(2x)^8}\]
yep
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The first one with out ( ) is what I meant ............
then the answer is \[\frac{2}{x^8}\]
Okay?! I am a little confused..........
\[x^{-8}=\frac{1}{x^8}\] So \[2x^{-8} = 2(x^{-8})=2\Big(\frac{1}{x^8}\Big)=\frac{2}{x^8}\]
okay thanks for breaking it down for me ! :)
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