[][]Note to teacher: Note from teacher: A pre-image point is rotated 270° clockwise. If the pre-image point had the coordinates (3, -5), what are the coordinates of its image point?
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convert (3,-5) into a polar coorinate; rotate, and then undo back into rectangular coords
or simply since this is a perpendicular we could determine the slope equation and translate into the perp
but polars is the route to go, a little simpler
given (x,y) convert to (r,t), and rotate to (r,t1) r = sqrt(3^2+5^2) = sqrt(34) t = tan-1(-5/3) t1 = tan-1(-5/3) - 270, make sure we stay in degrees convert back to rectangulars: (x1,y1) x1 = r cos(t1) y1 = r sin(t1)
t1 = 30.96 degrees if i did it right x1 = about 5 y1 = about 3 ..
which is what youd expect from a perpendicular arrangment like this; <3,-5> perps to <5,3>; from origin that equals (5,3)
great work amistre 64 , !!!
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