absolute value inequality. |3x-7|= -5, I get x=2/3, x

Question

absolute value inequality. |3x-7|>= -5, I get x>=2/3, x<=4...need help understanding graphing and interval notation....

anonymous · Answer

http://www.wolframalpha.com/input/?i= |3x-7|%3E%3D+-5 might help you undestand the graph

anonymous · Answer

rules for interval notations are http://en.wikipedia.org/wiki/Interval_%28mathematics%29#Notations_for_intervals

anonymous · Answer

x=[2/3,4]

anonymous · Answer

so would my answer be (infinity, 2/3] U [4, infinity)?

anonymous · Answer

dharam: please explain

anonymous · Answer

3/8+1/2+2/3
=(3*3+4*12+2*8)/24
=9+48+16/24
=73/24

anonymous · Answer

Sorry wrongly typed

anonymous · Answer

Here 2/3<=x<=4
so x lies beween 2/3 and 4 also since x cann't be sess then 2/3 or more the 4 so in other words (2/3,infinity) intersection(infinity,4)

anonymous · Answer