Ok, charges +q and -q on a dipole tha are equal.Where the dipole is through the y axis and its length is d. While a point perpendicular to the center of the charge is located at p. What is the magnitude of the diploes electric field at p? Do you use dot product to produce the magnitude and does it produce 0?

Question

Ok,  charges +q and -q on a dipole tha are equal.Where the dipole is through the y axis and its length is d. While a point perpendicular to the center of the charge  is located at p. What is the magnitude of the diploes electric field at p?  Do you use dot product to produce the magnitude  and does it produce 0?

anonymous · Answer

Well I don't know about dot product but if you sketch out the vectors of field you will see the y-component cancels out and the x-component is doubled. Hope that helps.

anonymous · Answer

That's what I saw in a tutorial video but was for a  rod  not a dipole which confusing. The had the same charge this has the opposite ones

anonymous · Answer

On the x components canceled.

anonymous · Answer

i think its  P/2[pi epsilon]p^3

anonymous · Answer

where P is the electric dipole moment of the dipole...

anonymous · Answer

Oh yea, the x-components cancel and the y-components double. Got the co-ordinate system switched around