Question

w=Cr^-2

Solve for r.

Answer 1

r= sqr(C/w)

Answer 2

\[w = Cr^{-2}\]
or is it
\[w = (Cr)^{-2}\]

ill assume the first
\[w = \frac{C}{r^2}\]
\[r^2 = \frac{C}{w}\]
\[r = \sqrt{\frac{C}{w}}\]

Answer 3

it was the first there was no parenthesis

Answer 4

can you tell me the steps you did?

Answer 5

rewrote \[w = Cr^{-2}\]as\[w=\frac{C}{r^2}\]

Answer 6

\[\text{multiplied by }r^2 \text{ and divided by }w \]
\[r^2=\frac{C}{w}\]
then I took the square root\[r = \sqrt{\frac{C}{w}}\]

Answer 7

okay

Answer 8

b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.)

Answer 9

what would i do first?

Answer 10

\[C=100x(3963x3963)\]