Question

How do I make this equal to zero?

y-(-3)=7/2 (x-(-1))

Answer 1

y+3=7/2(x+1), if you want y = to zero, 0=7/2(x+1)-3

Answer 2

\[0 = \frac{7 \times (x+1)}{2} - (y+3)\]

Answer 3

This was the original question.

Find an equation of the line that satisfies the given conditions.
Through
(−1, −3);
perpendicular to the line
2x + 7y + 8 = 0

Answer 4

Subtract 8 and 2x from both sides..
7y=-2x-8
Divide by 7
y=-2/7x-(8/7)

Now you want a line with the slope of 7/2 (perpendicular = opposite reciprocal) that goes through (-1,-3)
y=-3+7/2(x+1)
Distribute, y=-3+7/2x +7/2

Add 7/2 and -3, -1/2

So your line is y = 7/2x +1/2

Answer 5

YES! Thank you :)