How do I make this equal to zero?

y-(-3)=7/2 (x-(-1))

Question

How do I make this equal to zero?

y-(-3)=7/2 (x-(-1))

anonymous · Answer

y+3=7/2(x+1), if you want y = to zero, 0=7/2(x+1)-3

anonymous · Answer

$$0 = \frac{7 \times (x+1)}{2} - (y+3)$$

anonymous · Answer

This was the original question.

Find an equation of the line that satisfies the given conditions.
Through 
(−1, −3);
  perpendicular to the line 
2x + 7y + 8 = 0

anonymous · Answer

Subtract 8 and 2x from both sides..
7y=-2x-8
Divide by 7
y=-2/7x-(8/7)

Now you want a line with the slope of 7/2 (perpendicular = opposite reciprocal) that goes through (-1,-3)
y=-3+7/2(x+1)
Distribute, y=-3+7/2x +7/2

Add 7/2 and -3, -1/2

So your line is y = 7/2x +1/2

anonymous · Answer

YES! Thank you :)