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Ten points are chosen in a plane, no three of which are collinear. (a) How many triangles can be drawn if each of the vertices is at one of the given points? (b) How many of the triangles have two particular points making up one of the sides?
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I've got the first answer
its B i can't figure out lol
ok, I'll try.
ty:)
I go with a permutaion problem.
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If 2 points are taken for a side, aren't there 8 left?
yes thats the answer lol
ty:)
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