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√(17/2)
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\[\sqrt{\frac{17}{2}}\]that?
yes
\[\frac{\sqrt{34}}{2}\]
what if i had this:
(x-5)^2=√(17/2)
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wait how did you get that?
i did by Rationalizing Denomiator.
\[x^2-10 x+25 = \sqrt{\frac{17}{2}}\]
\[x=5 \pm \sqrt{34}/2\] <--- would that be my answer?
i think there is some mistake.
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here is the original problem: 2(x-5)^2=17
Oh, you mistyped. \[x-5 = \frac{17}{2}\]\[x = \frac{17}{2}+5\]
i think u can solve now.
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