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125 ^ 4/3
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\[125^{4/3} \]
Yes! That is the correct equation
\[\sqrt[3]{125^4}\]
\[\sqrt[3]{125^4}\]
I should subtract the exponents correct? and end up with 125 ^1? which would equal 125?
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Ooops! I was WAY OFF!!!
How do I solve this equation further?
\[\sqrt[3]{125^4}= 625\]
\[\sqrt[3]{(5^4)^3}\]
cubes cancel
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Ok - I vaguely remember this.
Thanks!
Well, I kind of skipped a step....|dw:1315769047891:dw|
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