Question

1+4/3log little (x-3) 4 = 11/3

Answer 1

what a pain

Answer 2

oh not really

Answer 3

ya i cant figure it out

Answer 4

1) subtract 1 from both sides get
\[\frac{3}{4}\log_{x-3}(4)=\frac{8}{3}\]

Answer 5

rather
\[\frac{4}{3}\log_{x-3}(4)=\frac{8}{3}\]

Answer 6

multiply both sides by 4/3to get
\[ \log_{x-3}(4)=\frac{8}{3}\times \frac{3}{4}=2\]

Answer 7

rewrite in equivalent exponential form to get
\[(x-3)^2=4\] and the solve the quadratic for x

Answer 8

\[x-3=2\]
\[x=5\]

Answer 9

you can forget about
\[x-3=-2\]
\[x=1\] because the base of a logarithm cannot be negative

Answer 10

thanks!