Question

write a parametrization for the equation of an ellipse at the origin crossing the x-axis at -3&3 and y-axis at -5&5

Answer 1

{3 cos(t), 5 sin(t)}

Answer 2

would you explain?

Answer 3

since ellipse =x^2/a^2+y^2+b^2=1
since sin^2(t)+cos^2(t)=1
x^2/9+y^2/25=1
(x/3)^2+(y/5)^2=1
sin(t)=x/3
cos(t)=y/5
3sin(t)=x
5cos(t)=y
9sin^2(t)+25cos^2(t)=1
I believe thats a clear explaination

Answer 4

i goofed on the x and y
cos(t)=x/3
sin(t)=y/5
3cos(t)=x
5sin(t)=y
9cos^2(t)+25sin^2(t)=1