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Mathematics 15 Online
OpenStudy (anonymous):

(1+9i)/(6+8i)

OpenStudy (anonymous):

6++17i -72 = -66+17 i

OpenStudy (anonymous):

how did you get that?

OpenStudy (anonymous):

its not multiplication its divison

OpenStudy (anonymous):

Multiply top and bottom by conjugate (6-8i)

OpenStudy (anonymous):

i did that i got -66+17i over 100+96i i dont think its right

OpenStudy (anonymous):

oh yes. estudier is right.

OpenStudy (anonymous):

1+9i)/(6+8i) [[6-8i)/6-8i)] multiply by conjecate

OpenStudy (anonymous):

The idea of using the conjugate is to get rid of the i on the bottom...

OpenStudy (anonymous):

oh wait i multiplied by 6+8i instead of 6-8i let me try again

OpenStudy (anonymous):

(a+b i )(a-bi) = a^+b^2

OpenStudy (anonymous):

(6+8i)(6-8i) = 36+64 =100

OpenStudy (anonymous):

it will be real number

OpenStudy (anonymous):

hope that helps.

OpenStudy (anonymous):

78+46i / 100?

OpenStudy (anonymous):

78+46i / 100 correct

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

you are welcome.

OpenStudy (anonymous):

Yes 78+46i / 100 is correct (:

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