If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation.
x – 2y = 2
x + 3y = 17

A. x + 3(–2y + 2) = 17
B. (2y + 2) + 3y = 17
C. x + 3(2y + 2) = 17
D. (–2y + 2) + 3y = 17

Question

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation.
x – 2y = 2
x + 3y = 17

A. x + 3(–2y + 2) = 17
B. (2y + 2) + 3y = 17
C. x + 3(2y + 2) = 17
D. (–2y + 2) + 3y = 17

anonymous · Answer

B

anonymous · Answer

just put x = 2y + 2 from 1st eqn in the place of x in 2nd eqn

anonymous · Answer

correct its B
x – 2y = 2                     x=2+2y sub this to the other eq
 x + 3y = 17 
(2+2y)+3y=17

anonymous · Answer

B. (2y + 2) + 3y = 17

x – 2y = 2 
x + 3y = 17
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solve eqn x – 2y = 2  for x. we get,
x=2y+2
plug this value of x in eqn x + 3y = 17 to get 
(2y+2) + 3y=17