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What are the zeros of the polynomial function: f(x) = x3 + x2 – 6x
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one solution
0,
2
x(x^2+x-6) 1st x=0, obviously. x^2+x-6=0 x=-0,5+-sqrt(0,5^2+6) x=-0,5+-2,5 2nd x=-0,5+2,5=2 3rd x=-0,5-2,5=-3
that answer is not one of the multiple choice answers that they give
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0, –2, –3 0, –2, 3 0, 2, –3 0, 2, 3
these are the answers they give to choose from
0, 2, -3 is what I said?
Well, meant atleast...
awesome thankx
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