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hello i need help with this Dif eq 1) dy/dx= x2 + y-1
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What are you doing to your differential equation?
Are you studying equations of the form: dy/dx + P(x) y = Q(x)
\[dy/dx = x^2 + y -1\]\[dy/dx-y= x^2-1\]\[dy-y=(x^2-1)dx\]Integrate both sides to get:\[-y^2/2=(x^3-3x)/3\]
+ C :)
@storm clearing the dx will give you a -y dx on the LHS
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@phi: Good catch...I should have typed in dy(-y) on the LHS...or put -ydy (simpler). For the original poster's info, the final answer is still correct
No, your equation becomes \( dy - y dx = (x^{2}-1) dx \) and you can not separate the x and y. See http://www.wolframalpha.com/input/?i=solve+dy%2Fdx+%3D+x%5E2+%2B+y+-1
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