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Mathematics 21 Online
OpenStudy (anonymous):

XY=2 CM XZ =5 CM AND M IS THE MIDPOINT OF XZ. YZ=? AND YM=? AND XM=? plz help

OpenStudy (anonymous):

there is not enough info in this to give an answer. what is the shape you have this data for? a picture would be nice.

OpenStudy (anonymous):

o ok

OpenStudy (anonymous):

|dw:1315869139136:dw|

OpenStudy (anonymous):

ok, if you think about this, it is pretty simple. first lets start with YZ

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

we know the distance from X to Y is 2 and the distance from X to Z is 5, right?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

so the answer to that could be 3?

OpenStudy (anonymous):

yes, you are exactly right ^^

OpenStudy (anonymous):

thnx and xm?

OpenStudy (anonymous):

well, we know M is half way between X and Z, right?

OpenStudy (anonymous):

and since XZ has length 5...

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

what is half of 5?

OpenStudy (anonymous):

2.5

OpenStudy (anonymous):

that is the length of XM

OpenStudy (anonymous):

ok and ym?

OpenStudy (anonymous):

well, you now know XM and XY

OpenStudy (anonymous):

YM is the difference in length of XM and XY

OpenStudy (anonymous):

ok so could the answer be 1?

OpenStudy (anonymous):

no, XM=2.5 and XY=2

OpenStudy (anonymous):

2.5-2=?

OpenStudy (anonymous):

0.5

OpenStudy (anonymous):

there you go ^^

OpenStudy (anonymous):

but i have a question

OpenStudy (anonymous):

ya?

OpenStudy (anonymous):

did you figure it out yourself or do you still have a question?

OpenStudy (anonymous):

can yz be 4?

OpenStudy (anonymous):

no, YZ must be 3

OpenStudy (anonymous):

the length of XZ is 5

OpenStudy (anonymous):

and the distance from X to Y is 2

OpenStudy (anonymous):

if YZ was 4, then adding the two segments together would tell you XZ had to be 6 long

OpenStudy (anonymous):

since XY+YZ=XZ, 2+3=5

OpenStudy (anonymous):

the sum of the lengths of the individual segments must equal the whole

OpenStudy (anonymous):

does that make sense?

OpenStudy (anonymous):

ok yes i do thank you very much

OpenStudy (anonymous):

glad to help ^^

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