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A ball is thrown upward with an initial velocity of 48 ft/s from a height 864 ft. h = -16t +48t +864 After how many seconds will the ball reach the ground? (i.e. For what positive value of t is h=0?)
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are you sure it is not h = -16t^2 +48t +864 ?
It is! Sorry, bad error!
0 = -16t^2 +48t +864 solve for t
you can divide out by 16
so it'd be -t^2 + 3t + 54 ?
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-t^2 + 3t + 54=0 yes
-t^2 + 3t + 54=0 you can even divide by -1 if you want, t^2-3t-54=0
do you then factor it?
yes
i can't think of any numbers that would work for that particular factoring :/
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two number that add up to -3, and multiply into -54?
-9 , 6 -9+6=-3 -9*6=-54
(x-9)(x+6)=0
so the answer would be, the ball will reach the ground in 9 seconds?
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