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how do I extract the square roots in 2(x-5)^2 = 17
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2(x^2+25-10x)=17 do it urself after it
isn't that just factoring?
yes
but that's not extracting the square :(
and it doesn't factor nicely.
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2x^2-20x+8
+8? 25(2) = 50 -17 = 33
x^2-10x+4 you must rooting
oh no you do this in two steps only
\[2(x-5)^2=17\] \[(x-5)^2=\frac{17}{2}\] \[x-5=\pm\sqrt{\frac{17}{2}}\] \[x=5\pm\sqrt{\frac{17}{2}}\]
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