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How do you solve this radical expression?
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\[\sqrt{10p ^{3}} \over \sqrt{27}\]
\[\frac{\sqrt{10p*p^{2}}}{\sqrt{9\times3}}\]\[\frac{p*\sqrt{10p}}{3\sqrt{3}}\]
Should you multiply top and bottom by \[\sqrt{3}\]?
oh geez I keep forgetting about leaving roots in the denominator
yes you would and you should get\[\frac{p*\sqrt{30p}}{9}\]
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\[P \times \sqrt{10P}\div3\sqrt{3}\]
multiplied by \[-3\sqrt{3}\]
90P/27 simplify 9 1/3 P
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