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Simplify the expression: 3 log 3 (6x – 4)
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3 log 3 (6x – 4) = 18 x log(3)-12 log(3) = 6 (3 x-2) log(3)
Is it a \[3\log_{3}(6x-4) \]
no
Is the base of the log given? Or just an empty space at where the base should be?
just an empty space. OK how about solving for if it's log to base 3 as well? :)
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If it's empty then it means a \[log_{10}\] So I'm thinking if the simplification can be \[lg 27+ lg(6x-4)^{3}\] Note: \[lg = log_{10}\]
OK how about solving for if it's log to base 3 as well? :)
Then it'll involve change of base... Great... Suddenly forgot how to solve that... I know but I'm not sure if it's correct
any one to help me solve \[3\log _{3}(6x-4)\]?
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