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what is the additive inverse of a/3
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-(a/3)
The 'additive inverse' is the thing you can add that will make it equal 0. 0 being the additive identity.
1 is the multiplicative identity! :)
\[{a \over 3} - {a \over 3} = 0 \qquad\quad\;\cdots(1) \]\[\\ {a \over 3} + \left(-{a \over 3}\right) = 0 \quad\cdots(2) \]And since we add -a/3 to make 0, we have -a/3 as the additive inverse.
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