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Mathematics 24 Online
OpenStudy (anonymous):

Graph, y=1. And put into y=mx+b form

OpenStudy (luffingsails):

So, no matter the value of x, y is always equal to one. |dw:1315937221982:dw| the equation would be: y = 0*x + 1

OpenStudy (luffingsails):

The coefficient of 0 on the x is provided by rise/run. In this case, the rise is 0.

OpenStudy (anonymous):

Can you give two points? (0,1) But by using the y=x+1 wouldn't that be (1,2) (2,3)?

OpenStudy (luffingsails):

No, I'm afraid not. The equation you just wrote is not at all the same. Just look at your points. The value y is not 1 (which is what it has to be). Not to mention the graph of this equation is something different. |dw:1315937589716:dw|

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