Question

how do I find the average rate of change of a function, y=x^3 + 1 over interval [2,3]?

Answer 1

\[AR=\frac{f(t_1)-f(t_2)}{t_1-t_2}\]

Answer 2

x=t

Answer 3

\[AR=\frac{(3^3+1)-(2^3+1)}{3-2}\]

Answer 4

THanks very much!

Answer 5

np

Answer 6

so if the function is g(x)=x^2 between [-1,1], the AR= 0? Do I have that right?

Answer 7

is average rate of change of the function, g(x)=x^2, over interval [-1,1] equal to 0?

Answer 8

yes