A cash register contains $341 dollars in $20, $5, and $2 bills. There are 28 bills in all, and three more twos than fives. How many bills of each kind are there?
x= number of $20 x+y+z=28 bills
y= number of $5 20x+5y+2z=341
z=number of $2 ? (Can you tell me how to get this? I have it, but don't know how to get it)

Question

A cash register contains $341 dollars in $20, $5, and $2 bills. There are 28 bills in all, and three more twos than fives. How many bills of each kind are there?
x= number of $20  x+y+z=28 bills   
y= number of $5    20x+5y+2z=341
z=number of $2   ? (Can you tell me how to get this? I have it, but don't know how to get it)

anonymous · Answer

There are 28 bills in all. Which means x+y+z=28, right?
Then you know that the register contains $341,
1x = $20, 1y = $5 and 1z = $2
so, making an equation out of that gives you 20x+5y+2z=341

anonymous · Answer

What about the equation for three more twos than fives?

anonymous · Answer

I know it y=z -3, but how do you get this equation?

anonymous · Answer

There are three more twos than fives.

There are x twenties
y fives
y+3 twos (Twos are THREE MORE than fives.)

or 

x twenties
z twos
z-3 fives (Fives are THREE LESS than twos.)

anonymous · Answer

Thank you so much!!!