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Find the general solution of the linear equation: y'=1+x+y+xy Not sure what the P(x) is when written as y'+P(x)=Q(x)
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WHY THE FREAK DID U POST IT A THOUSAND TIMES!?!?!?
this is my first time posting this question
rewrite \[\frac{dy}{dx}=y(x+1) +(x+1) = (x+1)(y+1)\] separate variables \[\frac{dy}{y+1} = (x+1) dx\] integrate both sides , then solve for y
you don't need to use y' +P(x)y = Q(x) since this is separable
ok
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