can someone help with this?
I am working on this one You are going to need to give me a little bit though as it will take a while to write out and explain.
ok take your time. im starting to get it but im getting stuck becauswe both F and G are fractions
a. yeah, that is going to make it pretty tedious. (F+G)(7) is the same of F(7)+G(7)
have you goteen an answer for a yet?
i think i got an aswer for d.
okay, what did you get for d?
\[\left\{ x \in \mathbb{R}|x \neq (5/2) \right\}\]
do you mean -5/2 ?
oh yeah thats what i wrote haha
and G is
\[\left\{ x \in \mathbb{R}| x \neq (7/3) \right\}\]
the ones that i have to add or subtract the fraction are the ones im stuck on...
would g. be those 2 put together by any chance?
my professor never went over the fraction part of this section -.-
only that the bottom cannot equal 0 but thats a given
So, you are semi-on theright track for G. Domain gets really strange with division. When you have something like DOM(F/G) you have to be especially careful when they are fractions. I would suggest using the invert and multiply method. so turm DOM(F/G) into DOM(F*1/G) this is nice way to look at it. now take this new equation and check for the Domain: The denominators cannot equal zero so that is what we will look at denominator of F is 2x+5 and denominator of 1/G is x^4-16 so x cannot equal either -5/2 or 2. does that make any sense? it is a very hard concept to explain using only text.
so you are saying ..? \[\left\{ x \in \mathbb{R} | x \neq (-5/2) and x \neq 2\right\}\]
for f. i dont have to subtract them right? just find the denominators that dont fit?
would the domain of a. be the same of g.? because the denominators are the same?
sorry for all the questions... :/
sorry said my last question wrong... would the domain of a. be the same of f.? because the denominators are the same?
yes, for f you just have to worry about G and F's denominators you don't actually have to do subtraction.
For G. Yes, because if you look at the equation: F/G you have 3 fractions in all (since both F and G are fractions) You have the F, G and the fraction F/G so you know that if the denominator equals 0, then the equation is undefined. Well, You need to worry about two denominators, the Denominator of F which is 2x+5 and you need to worry about the denominator of F/G which is G or (x^4-16)/(3x-7) so, the denominator of F is zero when x=-5/2 and the denominator of F/G is zero when G=0 and G=0 when x=2 does that make a little more sense?
and yes, the domains of A and F are the same!
oh wait a.-c. are different... its asking for simplest form?
Yes, A-C are not dealing with domains. for those your answers will be fractions.
would that just be ((7x-42)/(2x+5))+(((x^4)-16)/3x-7)?
or do i have to add them?
No, you are plugging 7 in for x for both of the equations.
oops yeah i forgot to put it like that on the computer but thats what i wrote but do i just keep it as is or do i add them together after?
it isn't "(F+G)*(7)" it's (F+G)(7) it is exactly like saying F(7)+G(7)
it would look like this before you simplify it: 7-6 7^4 -16 --------- + ----------- (2*7)+5 (3*7)-7
what about the x?
You need to add them together because it is asking you for the simpleist form. Be very careful as one small mistake during the addition process can mess up your answer bad.
oooooo! i get the (7) now! sorry >.< its a long night/morning haha
ok now how would i add them? do i get a common denominator?
yes, you will need to get the GCD.
Okay. I am going to post you my answers because I need to go to bed, it is 7AM and I have to drive for 4 hours tomorrow and wake up at 10:30AM :). I strongly suggest that you don't just copy my answers though because it sounds like you are starting to get it and if you don't actually finish the problems the process might not stick and you will be screwed for whenever you are tested on this. Also I strongly suggest you do them too because I'm human and can easily make mistakes so double checking answers is always good. Here is what I got: a. 45329/76 b. 3927/92 (that is after simplifying another fraction so make sure your's is as simplified as possible before comparing) c. C is undefined because F(6)=0 and F is the denominator of G/F d. x cannot be -5/2 e. x cannot be 7/3 f. x cannot be -5/2 or 7/3 g. x cannot be -5/2 or 2
If you have further questions I will be happy to answer them tomorrow or Friday. I know that won't help with this homework but knowing the process for Test, quizzes, and higher maths is more important than one homework grade!
for a. how is it /76 on the bottom?
i got 266
You are completely right! I'm not sure where my 76 came from but the bottom should be 266.
well thank you VERY much for your help ^_^ this helped me a lot getting an understanding :D Thanks again!
im in a hybrid online/inclass course and the teacher doesnt do much -.- i found my assistance now ^_^
No problem, sorry it took a while. I have explained this in person to multiple people and it is a lot easier in person; but hey, You got it and it only took like an hour lol. may I ask what math course this is for?
intermediate algebra starting in college so didnt want to go too high for my frist math class
first* i was in calc before i graduated highschool 2 1/2 years ago haha
getting a refresher for now but a lot of this i have forgotten because i didnt really have good math teachers. they all used the banking concept and i was one to use the problem-posing concept with my work so most of my work was by my hand -.-
was always good in math just not right now haha
yeah teachers make ALL the diffence I was lucky and my Highschool calc teacher was the best teacher I have ever had so It stuck with me really well, AND he was my Physics teacher so that was nice too. Anyway good luck!
im taking physics next year so i hope i still know you haha xD
thanks again i will be seeing you later! congrats on graduating by the way!
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