Question

find the equation of the line passing through the point (-2, 4) and perpendicular to y = -x + 4.

Answer 1

\[y-4=x-(-2)\]\[y=x+6\]

Answer 2

oops

Answer 3

it didn't show up but it's not -x it's -1/2x

Answer 4

-1/2?
no itsnot

Answer 5

like -one half x, I but in the fraction 1/2x but it only came up as -x

Answer 6

oh lol

Answer 7

what I mean is the question is y = -1/2x + 4

Answer 8

yeah sorry!

Answer 9

then the answer is\[y-4=2(x--2)\]\[y-4=2x+4\]\[y=2x+8\]

Answer 10

isnt it suppose to be y=-2x+8?

Answer 11

no coz the slope of the perpindicular line is the negative reciprocal
and here its -1/2
so the negative reciprocal of -1/2 = 2

Answer 12

ya, my fault, it suppose to be -(1/m).

Answer 13

:)

Answer 14

thanks guyss! (:

Answer 15

got any idea how to solve this? \[\int\limits_{0}^{1/3} \tan ^{5} \pi \theta \sec \pi \theta d \theta\]