Question

Factor the following
Y^4-16Y^3

Can someone explain why it is y = 0 and =16

The way i factored it i got y^2 (y-4)(y+4)
So i would get y = 0 y= 4 y=-4

Why is this wrong

Answer 1

y^3(y-16)

Answer 2

y = 0
&
y = 16

Answer 3

my answer yields the same results so why is one wrong and one not? Thanks by the way

Answer 4

that is wrong b/c y^3 is the common.

so you are left with y-16
so:

Y^3(y-16) = 0

y^3 = 0 y = 0
y-16 = 0 y = 16

Answer 5

are you getting it now?

Answer 6

Thanks

Answer 7

Welks.