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Solve the indefinite integral: e^((3(t^2))/2)
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B' e^(B) + C
i derived lol
way to early ....
Yeh... :P The integral is trickier.
1/6 (e^((3 t^2)/2) (2/t+2/(3 t^3)+2/(3 t^5)+10/(9 t^7)+70/(27 t^9)+70/(9 t^11)+O((1/t)^12))-i sqrt(6 pi))
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i havent played around with the e^(x^2) stuff yet
Just started diff equation course, lots and lots of integrals here, hehe. That's the expansion around 0 Dhashni, looks like at least, it's not helpful! :)
you will need to look at a series expansion to integrate that
Damnit...
Ok, thanks!
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