Question

which is a possible solution of 6+ square root of 3x^4+1 =10-2x^2 ?

Answer 1

subtract 6 from both sides and then square the result. solve for x

Answer 2

\[6+\sqrt{3x^4+1}=10-2x^2\]
\[\sqrt{3x^4+1}=4-2x^2\]
\[3x^4+1=(4-2x^2)^2=4 x^4-16 x^2+16\]

Answer 3

\[x^4-16x^2+15=0\]
\[(x^2-1)(x^2-15)=0\]
\[x^2=1\]
\[x=\pm1\]
\[x^2=15\]
\[x=\pm\sqrt{15}\]

Answer 4

so we have 4 "possible" solutions, but you have to check them to see which if any are correct

Answer 5

i think just 1 and -1 work

Answer 6

thank you so much :)

Answer 7

yw