Tim's bank contains quarters, dimes, and nickles. He has three more dimes than quarters and 6 fewer nickles then quarters. If tim has 63 coins write and solve an equation to find how many quarters tim has
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OpenStudy (anonymous):
d+q+n=63
3q+q+(q-6)=63
solve for q
OpenStudy (karatechopper):
how can that be 3q we r talking dimes and quarters should tht not be a 3d?
OpenStudy (anonymous):
sorry
d is dime
q is quarters
and n is nickles
(3+q)+q+(q-6)=63
q+q+q=66
3q=66
q=33
OpenStudy (karatechopper):
what about the 3 and 6?
OpenStudy (karatechopper):
wouldn't it be 9 + 3q?
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OpenStudy (anonymous):
which 3 and 6
OpenStudy (karatechopper):
3 for more dimes and 6 for nickles
OpenStudy (anonymous):
no it is -6 so it is 3-6 which is -3
OpenStudy (karatechopper):
so -3q=63?
OpenStudy (anonymous):
no so you have
3+q+q+q-6=63
3q-3=63
3q=63+3
3q=66
q=33
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OpenStudy (karatechopper):
it actually 22 not 33
OpenStudy (anonymous):
yeah sorry
OpenStudy (karatechopper):
ok medal and fan 4 u then!
OpenStudy (anonymous):
Solve the following equations for d,n and q:\[\{d=q+3,n=q-6,q+n+d=63\}\]\[\{q=22,n=16,d=25\} \]