Question

Find the equation of the line passing through the points (-2,-3) that is parallel to the line 5x-2y=10.

Answer 1

y=(5/2)x+3

Answer 2

Let's start with the piece of info that tells us that the line is parallel with 5x-2y = 10 cause that will give us the slope.

5x-2y = 10
-2y = -5x + 10
y = 5/2x + 2

from this we can see that our slope, m = 5/2.

Now let's use the slope that we found and find the equation of the line that passes a given point (-2, -3)

We know: y = mx +b
-3 = (5/2) (-2) + b
-3 = -5 + b
b = 2

Therefore the equation of the line is y= 5/2x + 2

Answer 3

where u get the 2 from?

Answer 4

whenu divided the -2

Answer 5

so the line is y=5/2x-5
find a line that has a slope of 5/2 and passes through (-2,-3)
so the line is y=5/2x+2

Answer 6

The second part?

Answer 7

We were just solving for b ( the point where the line passes through the y -axis)