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(X^2 - 7) / X^2 . limit as X reaches 0
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Doesn't exist, it diverges to negative infinity.
\[ \lim_{x\rightarrow 0} \frac{x^2-7}{x^2} = \lim_{x\rightarrow 0} \left(1 - \frac{7}{x^2}\right) = -\infty \]
sure? thanks
Yea sure :-D.
lim_(X->0) (X^2-7)/X^2 The limit of a quotient is the quotient of the limits: = (lim_(X->0) (X^2-7))/(lim_(X->0) X^2) Using the power law, write lim_(X->0) X^2 as (lim_(X->0) X)^2: = (lim_(X->0) (X^2-7))/(lim_(X->0) X)^2 The limit of X as X approaches 0 is 0: = -infinity
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