Lagrange Multipliers-System of Equations.....Could someone walk me through solving the system of equations y=z2x, x=z4y, (x^2)+2(y^2)=1

Question

amistre64 · Answer

your just adding in an extra variable, the L and solving for partials

anonymous · Answer

what happened with that problem from last night?

amistre64 · Answer

y=z2x, x=z4y,  what do these mean?

amistre64 · Answer

http://www.youtube.com/watch?v=ry9cgNx1QV8 this guy i think is one of the easiest to understand

anonymous · Answer

I just used z instead of lambda....when I have the calculator solve the system i get the correct answer...I just can not get there on my own. Lagrangeson- this is the question from last night

anonymous · Answer

find the points on the ellipse x^2 + 2y^2=1 where f(x,y)= xy has its extreme values.

anonymous · Answer

This is calculus multi variable right

anonymous · Answer

(±1/2√,1/2),(±1/2√,−1/2) is the correct answer

anonymous · Answer

yes sir

anonymous · Answer

did you convert the condition your were given into a function