Question

how do you rationalize the fraction:
1/(5 x √5−3 y √3)
please.

Answer 1

multiply denominator by \[5x \sqrt{5}+3y \sqrt{3} \]
and numerator by \[5x \sqrt{5} -3y \sqrt{3} \]

Answer 2

I did that and i got the numerator of course, what would you get for the denomiator, i think that is what's confusing me im not sure if anything cancels out

Answer 3

(a-b)(a+b) = a^2 - b^2
so numerator will be 125x^2 - 27 y^2

Answer 4

125x^2 - 27y^2

Answer 5

i meant denominator

Answer 6

(5x√5)^2=25*5x^2=125x^2

(3y√3)^2=9*3x^2=27y^2

Answer 7

thank you very much and the numerator would just be 5x5√+3y3√ then correct?

Answer 8

yes :)

Answer 9

alrighty thank you!

Answer 10

yw:)