A student wishes to dilute 50ml of a solution 0f 0.10 mol L^-1 calcium chloride to obtain ion concentrate of 0.02 mol L^-1.
What is the volume of the diltuted solution ?

Can someone pls explain step by step (:

Question

A student wishes to dilute 50ml of a solution 0f 0.10 mol L^-1 calcium chloride to obtain ion concentrate of 0.02 mol L^-1.
What is the volume of the diltuted solution ?

Can someone pls explain step by step (:

anonymous · Answer

$$\frac{mol}{L}=M$$
You can use the following formula to answer this:
$$M_1V_1=M_2V_2$$
Note that V is handled in terms of L so we times the 50ml by 10^{-3}.
$$0.10M*50(10^{-3})L=0.02M*V_2$$
We need to solve for V_2 so we will divide both sides by 0.02.
$$\frac{0.10M*50(10^{-3})L}{0.02M}=V_2$$
Notice that the M cancel and we are left with L which is what we are seeking.
$$0.25L=V_2$$
This can also be written as:
$$V_2=250ml$$
Now if you approach this logically, we're looking to dilute a concentration because the Molarity is going down. The implication here is that we have to add more water so our volume will go up. Note that we have a larger volume for V_2 than V_1.

mimi_x3 · Answer

wow~ ty Osirisis (:

anonymous · Answer

Happy to help. It lets me practice what I learned over the summer :)

mimi_x3 · Answer

lols okay (: