Question

Use elimination to solve the system.

6x-4y=12
3x+5y=-6

Answer 1

I am not understanding how you obtained the answers

Answer 2

Multiply equation (2) by \(-2\) and add it to equation (1), the system will become:
\(6x-4y=12\) ... (1)
\(-6x-10y=12\) .. (2)
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\(-14y=24 \implies y=-\frac{12}{7}\). Now plug this value of \(y\) in either equation to get the value of \(x\). Plugging in (1) yields \(6x-4(-\frac{12}{7})=12 \implies x=\frac{6}{7}\).

Answer 3

So, \(y=-\frac{12}{7}\) and \(x=\frac{6}{7}\).

Answer 4

Thank you so much! I had the -12/7 but couldn't figure out rest of answer when I plugged it in. I kept getting 108/7

Answer 5

I will do this part step by step, so you can see where you made your mistake. First, multiply both sides by \(7\) for simplicity: \(42x-4(-12)=84 \implies 42x+48=84 \implies 42x=36 \implies x=\frac{36}{42}\) Divide top and bottom by \(6\) to get \(x=\frac{6}{7}\).

Answer 6

Got it thank you

Answer 7

You're welcome!