solve -3^2+2^0+27^(-2/3)
so -3^2 is 9 and 2^0 is 1
which 9+1=10
then 27^-2/3= 1/27^(2/3) where do i go from there?

Question

solve -3^2+2^0+27^(-2/3) 
so -3^2 is 9 and 2^0 is 1 
which 9+1=10 
then 27^-2/3= 1/27^(2/3) where do i go from there?

saifoo.khan · Answer

when ever you have a negative exponent, you have to flip the fraction.

bigdog · Answer

i did that with the 27 its now 1 over 27 does the 2/3 make the 27 1/9?

myininaya · Answer

(-3)^2=9
-3^2=-9
2^0=1
-3^2+2^0+27^(-2/3)
-9+1+1/27^(2/3)
-8+1/(3*3)
-8+1/9
-8*9/9+1/9

-71/9

bigdog · Answer

thanks that helped alot becaues i was getting lost

anonymous · Answer

Ok your right so far with 1/27 ^(2/3) when you flipped the negative exponent, now you do 3√27 = 3 and take the 3, and do 3^2 which is 9, then you should be able to figure from there..

myininaya · Answer

-3^2 is different from (-3)^2