Question

(x+2)^2-(x-3)^2=3x-11,
do usual order of operation apply???

Answer 1

yes.

Answer 2

exponent 1st then add.

Answer 3

x^2 + 4x + 4 -(x^2 - 6x+9) = 3x -11
x^2 + 4x + 4 - x^2 + 6x - 9 = 3x -11
10x - 5 = 3x-11
2x = -6
x = -3

Answer 4

actually mimi acording to my textbook you are wrong

Answer 5

woops sorry I did it too fast , i will do it again xD

Answer 6

x^2 + 4x + 4 - x^2 + 6x - 9 = 3x -11
10x - 5 = 3x -11
7x = -6
x = -6/7
Is it right :?

Answer 7

yes

Answer 8

yay ! i just made a stupid mistake before sorry xD

Answer 9

could we go through you answer together?

Answer 10

where did you get the 4x from?

Answer 11

Um , okay xD
Well, I expanded (x+2)^2 , you know how to expand right ?

Answer 12

yes (x^2+4)

Answer 13

No, that's not expansion
(x+2)(x+2) <-- this is expansion

Answer 14

oh, i got this

Answer 15

thanks mimi

Answer 16

yw (:
If you still need help, i can help you (:

Answer 17

lemme try and solve it

Answer 18

Okay (:

Answer 19

when expanding the 2nd term is is -(x-3)-(x-3) or (x-3)(x-3)???

Answer 20

No, don't do that it will get you confused.
Well, when I do it i expand it first so (x-3)^2 = x^2 - 6x + 9
Then , -(x^2 - 6x + 9) -> -x^2 + 6x - 9
Do you get it ?

Answer 21

i know how to expand..

here is the right way.

Answer 22

LOL, it looks more complicated =/

Answer 23

hahahaha!

Answer 24

Loooooooool

Answer 25

Btw, I don't get your way of expanding it xD

Answer 26

its not simple, you need a great mind to do that and a lot of courage too.
:)))

Answer 27

@mimi, dont get it, I know how to expand, I am wondering if the - sign makes thebefore the second term (x-3) negative

Answer 28

LOL, courage!? you can use an easier way that is called smart xD
Put the negative sign outside of the bracket
-(x^2 + 6x-9) -> -x^2 - 6x + 9 , Do you get it ?

Answer 29

yes

Answer 30

distributing the - sign

Answer 31

yup :D