I'm supposed to use the point and the slope to find three additional points through which the line passes. I have point; (2,1) & Slope; m=0.

Not a clue on how to do this!

Question

I'm supposed to use the point and the slope to find three additional points through which the line passes. I have point; (2,1) & Slope; m=0.

Not a clue on how to do this!

anonymous · Answer

good

anonymous · Answer

?

anonymous · Answer

A slope of 0 is just a horizontal line

anonymous · Answer

If the slope is 0, the the y-value is constant. All your points are (x,1).

anonymous · Answer

Well, what if is the slope is undefined then?

anonymous · Answer

then it s a vertical line

anonymous · Answer

Oh! Thank youu(:

anonymous · Answer

Rise/Run
If you rise 0 and run any number (horizontal line), the slope will always be 0 because you have a 0 in the numerator. (0/x)
If you rise any number and run 0 (vertical line), the slope will be undefined because you have 0 in the denominator. (x/0)