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I'm supposed to use the point and the slope to find three additional points through which the line passes. I have point; (2,1) & Slope; m=0. Not a clue on how to do this!
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good
?
A slope of 0 is just a horizontal line
If the slope is 0, the the y-value is constant. All your points are (x,1).
Well, what if is the slope is undefined then?
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then it s a vertical line
Oh! Thank youu(:
Rise/Run If you rise 0 and run any number (horizontal line), the slope will always be 0 because you have a 0 in the numerator. (0/x) If you rise any number and run 0 (vertical line), the slope will be undefined because you have 0 in the denominator. (x/0)
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