Question

Help ...Multiply
(x^8+x^7)(x^8+x^7-x^6)
would I just add the exponents in each?
x^36???

Answer 1

no because you have a sum

Answer 2

you actually have to do 6 multiplications, and each of those you would add the exponents

Answer 3

or is the answer this x^16+2x^15-x^13

Answer 4

What? where is the sum?

Answer 5

That is correct I think. Good job!

Answer 6

\[(x^8+x^7)(x^8+x^7-x^6) \]
\[x^8\times x^8+x^8\times x^7+x^8\times (-x^6)+x^7\times x^8+x^7\times x^7+x^7\times (-x^6)\]

Answer 7

what you wrote is correct!

Answer 8

Yay me! :) thanks guys!!!!

Answer 9

\[(x^7)(x+1)(x^6)(x^2+x-1)=x^{7+6}(x+1)(x^2+x-1) \]
\[=x^{13}(x^3+x^2-x+x^2+x-1)=x^{13}(x^3+2x^2-1)=x^{16}+2x^{15}-x^{13}\]

Answer 10

gj!