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( x^2 + x + 1) / (x-1). find the limit as x reaches 1
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are you sure with your equation?
3
oh yes, people say it does not exist but i think the answer is 3
and how did you conclude that?
using the l'hopital rule
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first get the derivatives then put the limit in.
i have another question, can you help me with it?
(x^3 - 7x) / X^3. find limit as x reaches 0. is the answer 1 or does not exist?
it dose not exist because at the last x you still get over 0.
did you try long division?
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\[\lim_{x\rightarrow 1}\frac{x^2+x+1}{x-1}=\frac{3}{0}=\infty\]
okay, thanks
\[\lim_{x\rightarrow 0}\frac{x^3-7x}{x^3}=\lim_{x\rightarrow 0}\frac{3x^2-7}{3x^2}=\frac{-7}{0}=\infty\]
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