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Use the substitution method to solve the following system of equations. 3x+5y=3 x+2y=0
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solve the second equation for x
x=-2y
then 3x-5(-2y)=3
isnt it 3(-2y)-5y=3?
oh yeah it is
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-6y-5y=3 -11y=3 ---- --- -11 -11 y=3/-11
But my choices are (6,1) (1,-3) (6,-3) (1,1)
it is (6,-3)
if you dont mind my asking, why?
okay,; 3(-2y)+5y=3 -6y+5y=3 -1y=3 y=-3
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i see! Thank you
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