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Mathematics 22 Online
OpenStudy (anonymous):

what is (x+h)^1.5

OpenStudy (anonymous):

(x+h)^(3/2) = sqrt[(x+h)^3] = (x+h) sqrt(x+h)

OpenStudy (anonymous):

you want the series expansion?

OpenStudy (anonymous):

I suppose not, because I don't even know what that is, but, I am trying to find the derivate of f(x)=(6x)^1.5-(4x)^5 therefore what is f'(x)=lim h>0 {[6(x+h)^1.5-4(x+h)^5] - [(6x)^1.5-(4x)^5]}/h

OpenStudy (anonymous):

dervative*

OpenStudy (anonymous):

DERIVATIVE*

OpenStudy (anonymous):

curiously it can be done with the series, but there are other tricks

OpenStudy (anonymous):

srry I cant be of more help now, g2g, but if you are interested in the series method do http://www.wolframalpha.com/input/?i=lim+h+to+0+%28 [6%28x%2Bh%29^1.5-4%28x%2Bh%29^5]+-+[%286x%29^1.5-%284x%29^5]%29%2Fh

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