Question

Can't figure out how to solve (factoring quadratic equations):
4x^2 +7x = 2

Answer 1

first make it equal to 0 by making the equationb 4x^2+7x-2 =0. then use teh quadratic formula

\[x = -b + or - \sqrt{b ^{2}-4ac}/ 2a\]

Answer 2

Factored Wrong... The answer would end up being (x-2) (4x-1)=0 or x=2 and x=1/4

Answer 3

Would you be able to outline step by step - not really understanding this at all. Issue seems to be when the 'c' is less than 'b' - can't figure out how to solve. THANK YOU!

Answer 4

Set equal to zero: 4x^2=7x-2=0
Plug the standard form equation into the quadratic formula: \[-7\pm \sqrt{7^2-4(4)(-2)}/2(8)\]
Simplify: \[-7\pm \sqrt{49+32}/8\]
\[-7\pm \sqrt{81}/8\]
\[(-7\pm9)/8\]
Solve for X: \[(-7+9)/8=.25 or 1/4\]
and \[(-7-9)/8= -2\]