Question

The surfaces intersect in a space curve C. Determine the projection of C onto the xy-plane.
The paraboloids x^2+y^2+ z=4 and x^2 +3y^2=z

Answer 1

doesnt that amount to z=0? no, it doesnt does it

Answer 2

that looks to be a good description ....

Answer 3

x^2+y^2+ z-4 = x^2 +3y^2 - z

x^2+ y^2 +z -4
-x^2 -3y^2 +z
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-2y^2 +2z -4 seems to be where they meet at

Answer 4

i cant get wolfram to come up with a plot for it ....

Answer 5

id say it projects onto the y axis