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1/5(x-2)=-2/5 (x-1)
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what are you asking for? simplification? proof?
x = 4/3
\[\frac{1}{5(x-2)} = \frac{-2}{5(x-1}\] \[5(x-1)=-2(5(x-2))\] \[5x-5 = -2(5x-10)\] \[5x-5=-10x+20\] \[5x+10x=-20+5\] \[-15x=-15\] \[x=\frac{-15}{-15}\] \[x=-1\]
mine is right i think.
x=1
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sorry in the last step \[x = -15/-15\] \[=> x = 1\]
Um I dont think that x = 1
Substitute it back in and see xD
x-2 is in numerator not in denom.
Saifoo is right xD http://www.wolframalpha.com/input/?i=1%2F5%28x-2%29%3D-2%2F5+%28x-1%29
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