Question

This is a Quadratic Equation, solve it by factoring please.Also please explain.
3x^2+22x+15=5(x+1)

Answer 1

3 x^2+22 x+15 = 5 (x+1)
Expand out terms on the right hand side:
3 x^2+22 x+15 = 5 x+5
Subtract (5 x+5) from both sides:
3 x^2+17 x+10 = 0
Solve the quadratic equation by completing the square:

Divide both sides by 3:
x^2+(17 x)/3+10/3 = 0
Subtract 10/3 from both sides:
x^2+(17 x)/3 = -10/3
Add 289/36 to both sides:
x^2+(17 x)/3+289/36 = 169/36
Factor the left hand side:
(x+17/6)^2 = 169/36
Take the square root of both sides:
abs(x+17/6) = 13/6
Eliminate the absolute value:
x+17/6 = -13/6 or x+17/6 = 13/6
Subtract 17/6 from both sides:
x = -5 or x+17/6 = 13/6
Subtract 17/6 from both sides:
x = -5 or x = -2/3

Answer 2

that is as long as its 3x squared.

Answer 3

3x^2 + 15x + 2x + 10 = 0

3x(x+ 5) + 2(x+5) = 0

(x+5)(3x+2) = 0

x = -5, -2/3

Answer 4

Solved by factoring

Answer 5

thnnks everyone