Question

write the equation of the line that passes through (-5,8) and (-3,-8)

Answer 1

m=(y2-y1)/(x2-x1)



m=(-8-8)/(-3-(-5))



m=(-16)/(-3-(-5))



m=(-16)/(-3+5)



m=(-16)/(2)



m=-8



So the slope of the line that goes through the points is m=-8



Now let's use the point slope formula:



y-y1=m(x-x[1])



y-8=-8(x--5)



y-8=-8(x+5)



y-8=-8x-8(5)



y-8=-8x-40



y=-8x-40+8



y=-8x-32


So the equation of the line that goes through the two points is y = -8x-32